Question

Given the reaction at STP 2KCI03(s) → 2KCI(s) + 302(9) What is the total number of liters of 02(9) produced from the complete decomposition of 0.500 mole of KCIOz(s)?

Answer 1

0.500 mole of KClO3(s) will produce 0.750 moles of O2(g), which at STP, converts to 16.8 liters of O2(g).

Step-by-step explanation:

The question involves determining the total number of liters of O2(g) produced from the complete decomposition of 0.500 mole of KClO3(s) at Standard Temperature and Pressure (STP). According to the stoichiometry of the provided reaction,

2 KClO3(s) → 2 KCl(s) + 3 O2(g)

we see that 2 moles of KClO3 yield 3 moles of O2. Therefore, 0.500 mole of KClO3 would yield half of 1.5 moles of O2, which is 0.750 moles. At STP, 1 mole of a gas occupies 22.4 liters, so 0.750 moles will produce:

0.750 moles × 22.4 liters/mole = 16.8 liters of O2(g)