Question

The lengths of the sides of a right triangle are 10 in., 24 in., and 26 in. What is the area of the triangle?

Answer 1

`Solution,\\Let~a=10in.,~b=24in.~and~c=26in.\\Semiperimeter(s) = (a+b+c)/(2)= (10+24+26)/(2) = 30in.\\Now,\\Area~of~triangle = √(s(s-a)(s-b)(s-c)) \\~~~~~~~~~~~~~~~~~~~~~~~~=√(30(30-10)(30-24)(30-26)) \\~~~~~~~~~~~~~~~~~~~~~~~~=√(30(20)(6)(4)) = √(14400)=120sq.inches`