asked 32.3k views
1 vote
Types of hybridization exhibited by the C atoms in propene, CH3CHCH2, include:

Isp II. sp2 III. sp3
(A) I only
(B) III only
(C) I and II only
(D) II and III only
(E) I, II, and III"

1 Answer

4 votes

Final answer:

In propene, carbon atoms 1 and 4 exhibit tetrahedral geometry with sp³ hybridization, while carbon atoms 2 and 3 have linear geometries and are classified as sp hybrids.

Step-by-step explanation:

Carbon atoms 1 and 4 have four single bonds and are thus tetrahedral with sp³ hybridization. Carbon atoms 2 and 3 are involved in the triple bond, so they have linear geometries and would be classified as sp hybrids.

answered
User Andre Motta
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