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What is the total capacitance of a circuit con-taining three capacitors in parallel with capacitances of .02 microfarad, .05 microfarad, and .10 microfarad, respectively?

A. 170 μF.
B. 0.125 μF.
C. 0125 μF.

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User Satanas
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1 Answer

7 votes

Final answer:

The total capacitance of the circuit containing three capacitors in parallel with capacitances of 0.02 µF, 0.05 µF, and 0.10 µF is 0.17 µF.

Step-by-step explanation:

When capacitors are connected in parallel, the total capacitance is the sum of the individual capacitances. In this case, the total capacitance would be 0.02 µF + 0.05 µF + 0.1 µF = 0.17 µF. Therefore, the correct answer is A. 170 μF.

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User Letseatlunch
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