Final answer:
To find the grams of cobalt(III) chromate in 4.55 moles, calculate the molar mass of the compound and multiply by the number of moles. The molar mass of cobalt(III) chromate is 465.854 g/mol, and multiplying this by 4.55 moles gives approximately 2119.64 grams.
Step-by-step explanation:
To calculate the grams of cobalt(III) chromate present in 4.55 moles of the compound, we need to know the molar mass of cobalt(III) chromate. Assuming the formula for cobalt(III) chromate is Co₂(CrO₄)₃, we must first calculate its molar mass. We do this by summing the molar masses of all atoms in the formula:
- Cobalt (Co): 58.933 g/mol x 2 = 117.866 g/mol
- Chromium (Cr): 51.996 g/mol x 3 = 155.988 g/mol
- Oxygen (O): 16.00 g/mol x 12 = 192.00 g/mol
The molar mass of cobalt(III) chromate = 117.866 g/mol + 155.988 g/mol + 192.00 g/mol = 465.854 g/mol.
Now, we multiply the molar mass by the number of moles to find the mass:
Mass in grams = Molar mass x Number of moles = 465.854 g/mol x 4.55 mol ≈ 2119.6407 grams.
There are approximately 2119.64 grams of cobalt(III) chromate in 4.55 moles of the compound.