Question

Multiplying binomials assignment multiply.
(1/2y-50)(3/5y+10)

Answer 1

The expression
`\(((1)/(2y) - 50)((3)/(5y) + 10)\)` simplifies to
`\((3)/(10y^2) - (25)/(y) - 500\)` after distribution, simplification, and combining like terms.

the expression
`\(((1)/(2y) - 50)((3)/(5y) + 10}\) )` the distributive property.

Given expression:
`\(((1)/(2y) - 50)((3)/(5y) + 10)\)`

First, let's distribute
`\((1)/(2y)\)` to both terms inside the second parenthesis, and then distribute
`\(-50\)` to both terms inside the second parenthesis:

`\((1)/(2y) * (3)/(5y) + (1)/(2y) * 10 - 50 * (3)/(5y) - 50 * 10\)`

Now, perform the multiplication:

`\((3)/(10y^2) + (10)/(2y) - (150)/(5y) - 500\)`

Simplify each term:

`\((3)/(10y^2) + (5)/(y) - (30)/(y) - 500\)`

Combine like terms:

`\((3)/(10y^2) - (25)/(y) - 500\)`

Hence, after simplification, the expression
`\(((1)/(2y) - 50)((3)/(5y) + 10)\)` simplifies to
`\((3)/(10y^2) - (25)/(y) - 500\).`

complete the question

Solve the binomial. (1/2y - 50)(3/5y + 10)