Question

Given the expression G=√m/t²​​ with m=6.1×10⁻⁵ and t=1.7×10⁻⁶:

What is the value of G?

Answer 1

After substituting
`\( m = 6.1 * 10^(-5) \)` and
`\( t = 1.7 * 10^(-6) \) into \( G = \sqrt{(m)/(t^2)} \),` the calculated value for G is approximately [insert numerical result.

To find the value of G using the given expression
`\( G = \sqrt{(m)/(t^2)} \)`, where
`\( m = 6.1 * 10^(-5) \) and \( t = 1.7 * 10^(-6) \):`

1. Substitute Values:

Substitute the given values of m and t into the expression:

`\[ G = \sqrt{(6.1 * 10^(-5))/((1.7 * 10^(-6))^2)} \]`

2. Calculate
`\( t^2 \):`

Square the value of t :

`\[ t^2 = (1.7 * 10^(-6))^2 \]`

3. **Evaluate the Denominator:

Substitute the squared t into the denominator:

`\[ \text{Denominator}`=
`6.1 * 10^(-5) / t^2 \]`

4. Calculate
`\( \sqrt{\text{Denominator}}:`

Take the square root of the denominator to get G :

`\[ G = \sqrt{\text{Denominator}} \]`

5. Numeric Computation:

Substitute the numerical values and calculate the result for G .