Question

You perform form a wavelength scan of candidate, a compound you recently synthesised and you note that the absorbence at potential drug (276) 10.632 while using 0.100 solution in a 1.000 em cuvette. through mass spectrometric analysis, you confirm the elemental composition and calculate the molar mass to be 180.158 g/mol. what is the moler absorptivity of your drug target at 276nm?

Answer 1

To calculate the molar absorptivity of the drug target at 276 nm, use Beer's Law with the provided values to find that the molar absorptivity is 106.32 L·mol⁻¹·cm⁻¹.

Step-by-step explanation:

To calculate the molar absorptivity (extinction coefficient, ε) of your drug target at 276 nm, we can use Beer's Law. Beer's Law states that absorbance (A) is equal to the molar absorptivity (ε) multiplied by the concentration (c) and the path length (l).

In your case, the path length is 1.000 cm, and you provided an absorbance of 10.632 at a concentration of 0.100 M.

The formula to calculate molar absorptivity is:

A = ε × c × l

By rearranging the formula to solve for molar absorptivity, we get:

ε = A / (c × l)

Plugging in your values, we find:

ε = 10.632 / (0.100 mol/L × 1.000 cm) = 106.32 L·mol⁻¹·cm⁻¹.

Therefore, the molar absorptivity of your drug target at 276 nm is 106.32 L·mol⁻¹·cm⁻¹.