Final answer:
In its more stable chair conformation, galactose contains a six-membered ring in which all the substituents, except the -OH group indicated in the question, are equatorial.
Step-by-step explanation:
In its more stable chair conformation, galactose contains a six-membered ring in which all the substituents, except the -OH group indicated in the question, are equatorial. T
o draw the chair conformation of galactose, you need to start with a hexagon to represent the six-membered ring. Place the -OH group in the equatorial position, pointing downwards. The other substituents can be arranged accordingly.