Question

The knobcone gene has two alleles that segregate within a population of loblolly pine. In this population of loblolly pine, you observe two genotypes with frequencies of 0.75 and 0.25. The fitness of the genotype with a frequency of 0.75 is equal to 1.0, whereas the fitness of the other genotype is 0.8. What is the mean fitness at this locus within this population?

A. 0.8
B. 0.95
C. 0.85
D. 0.875

Answer 1

The mean fitness at this locus within this population is 0.95.

Step-by-step explanation:

The mean fitness at this locus within this population can be calculated by multiplying the frequency of each genotype by their respective fitness and then summing the products.

Genotype frequency 1: 0.75 x 1.0 = 0.75

Genotype frequency 2: 0.25 x 0.8 = 0.2

Total fitness: 0.75 + 0.2 = 0.95

Therefore, the mean fitness at this locus within this population is 0.95.