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A study of 75 bolts of carpet showed that their average length was 72.2 yards. The standard deviation of the population is 2.6 yards. Which of the following is the 98% confidence interval for the mean length per bolt of carpet?

A) 70.1 μ 73.3
B) 71.5 μ 72.9
C) 72.0 μ 73.5
D) 70.6 μ 73.0
E) 71.0 μ 73.2

asked
User Duckman
by
8.2k points

1 Answer

5 votes

Final answer:

The 98% confidence interval for the mean length of carpet from a sample with a mean of 72.2 yards and a population standard deviation of 2.6 yards is approximately 71.5 to 72.9 yards. The Z-score for 98% confidence is 2.33, leading to a margin of error of 0.699 when applied to the given standard deviation and sample size. Therefore, option B) 71.5 μ 72.9 is the correct answer.

Step-by-step explanation:

To find the 98% confidence interval for the mean length of carpet from a sample of 75 bolts with a mean of 72.2 yards and a known population standard deviation of 2.6 yards, we need to use the formula for the confidence interval of the mean with a known population standard deviation:

Confidence Interval = μ ± (Z * (σ / √n))

Where μ is the sample mean, σ is the population standard deviation, n is the sample size, and Z is the Z-score corresponding to the desired confidence level.

For a 98% confidence level, the Z-score is approximately 2.33 (this can be found in Z-score tables or using statistical software). Thus, the margin of error (ME) can be calculated as:

ME = Z * (σ / √n) = 2.33 * (2.6 / √75) = 2.33 * 0.3 ≈ 0.699

Therefore, the confidence interval is:

72.2 ± 0.699

Which gives us the interval:

72.2 - 0.699 = 71.501 (approximately 71.5)

and

72.2 + 0.699 = 72.899 (approximately 72.9)

Thus, the 98% confidence interval for the mean length per bolt of carpet is approximately 71.5 to 72.9 yards.

The correct answer from the options provided would be B) 71.5 μ 72.9.

answered
User Alfred Godoy
by
8.0k points
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