Question

Consider the two methods (within the same class)

public static int foo(int a, String s)
{
s = "Yellow";
a=a+2;
return a;
}
public static void bar()
{
int a=3;
String s = "Blue";
a = foo(a,s);
System.out.println("a="+a+" s="+s);
}
public static void main(String args[])
{
bar();
}
What is printed on execution of these methods?
(a) a = 3 s = Blue
(b) a = 5 s = Yellow
(c) a = 3 s = Yellow
(d) a = 5 s = Blue
(e) none of the above.

Answer 1

The value of a is 5 and the value of s is Blue.

Step-by-step explanation:

The methods defined are:

• public static int foo(int a, String s) {
  s = "Yellow";
  a=a+2;
  return a;
  }
• public static void bar() {
  int a=3;
  String s = "Blue";
  a = foo(a,s);
  System.out.println("a="+a+" s="+s);
  }
• public static void main(String args[]) {
  bar();
  }

In the foo method, the value of the string parameter s is changed to "Yellow". The value of the integer parameter a is incremented by 2 and returned. In the bar method, the integer variable a is assigned the value 3, and the string variable s is assigned the value "Blue". The foo method is then called with the arguments a and s. The returned value of the foo method is assigned to a. The System.out.println statement prints the values of a and s which are 5 and "Blue" respectively.