Name = "skye homsi" name1 = ()name2 = name_1.swapcase()print(name2) What is the output from the above code? a. "Skye Homsi" b. "SKYE HOMSI" c. &quo…

Question

Name = "skye homsi" name1 = ()name2 = name_1.swapcase()print(name2)

What is the output from the above code?
a. "Skye Homsi"
b. "SKYE HOMSI"
c. "skye homsi"
d. "sKYE hOMSI"

Answer 1

The code has a syntax error, but assuming it is corrected, the swapcase() method would change 'skye homsi' to 'SKYE HOMSI'. Therefore, the correct output, if the code ran correctly, would be b. 'SKYE HOMSI'.

Step-by-step explanation:

The Python code provided has a syntax error and will not execute as it stands. However, assuming that the error is fixed and based on the use of the swapcase() method, which swaps the case of each letter in a string, the output should invert the case of the original 'skye homsi'.

That being said, the code has an error due to a missing variable name. If we assume the intent was to have name1 have the value of name, and then apply swapcase() to name1, the variable name2 will contain the swapped case version of name1. Correcting the typo and considering this, the output would be 'SKYE HOMSI'.

If the intention was to swap the case of name, which is 'skye homsi', using the swapcase() method, then after the correction, the correct answer would indeed be option b. 'SKYE HOMSI'.