Question

A magnetic field of 1wbm−2 is applied along the thickness of a semiconducting crystal of length 10 mm, breadth 5 mm and thickness 1 mm. A current of 10 mA flows along the longest part of the specimen and the Hall voltage across the width is found to be 40μV. What will be the Hall coefficient of the semiconducting crystal?

Answer 1

The Hall coefficient of the semiconducting crystal is 0.4 m^3/A s.

Step-by-step explanation:

The Hall coefficient can be determined using the formula:

RH = VH/(I*B),

where RH is the Hall coefficient, VH is the Hall voltage, I is the current, and B is the magnetic field.

In this case, the Hall voltage is given as 40 μV, the current is 10 mA (or 0.01 A), and the magnetic field is 1 Wbm−2. Plugging in these values, we get:

RH = (40 μV)/(0.01 A * 1 Wbm−2),

RH = 40 * 10^-6 V / (0.01 A * 1 Wbm−2),

RH = 4 * 10^-3 / (0.01 * 1) m^3/A s,

RH = 0.4 m^3/A s.