Question

Where does f(x)=csc(x) have a verticle asymptotes on [0,2π] ? Select all that apply

Answer 1

The function f(x) = csc(x) has vertical asymptotes at x = 0, x = π, and x = 2π.

Step-by-step explanation:

The function f(x) = csc(x) has vertical asymptotes where the cosecant function is undefined. The cosecant function is undefined when the sine function is equal to zero because dividing by zero is undefined in mathematics. In the interval [0, 2π], the sine function equals zero at x = 0, x = π, and x = 2π. Therefore, the function f(x) = csc(x) has vertical asymptotes at these values.