asked 195k views
3 votes
A spherical, concave shaving mirror has a radius of curvature of32.0 cm.

what is the magnification of a person's face when it is 12.0cm to the left of the vertex of the mirror?

asked
User Samzmann
by
8.3k points

1 Answer

4 votes

The magnification of the person's face is 2.0. This means that the image of the face will appear twice as large as the actual face.

A spherical, concave shaving mirror has a focal length of half its radius of curvature. So, in this case, the focal length would be:

f = R / 2 = 32.0 cm / 2 = 16.0 cm

When a person's face is 12.0 cm to the left of the vertex of the mirror, the object distance (do) is -12.0 cm (since it's on the left side). We can use the mirror equation to find the image distance (di):

1/do + 1/di = 1/f

1/-12.0 cm + 1/di = 1/16.0 cm

Solving for di, we get:

di = -24.0 cm

The magnification (M) is then given by:

M = -di / do = -(-24.0 cm) / (-12.0 cm) = 2.0

Therefore, the magnification of the person's face is 2.0. This means that the image of the face will appear twice as large as the actual face.

answered
User Manjunath
by
8.6k points