Question

Which XXX and YYY will find the minimum value of all the elements in the array? Choices are in the form XXX/YYY.

int userVals [NUM_ROWS] [NUM_COLS];
int minVal = userVals [θ][θ];
for (i=0;i< NUM_ROWS;
for (j=0;j){
if (XXX) { NNUM_COLS; ++j){ YYY;
}
}
a. uservals [i]b. uservals [j]c. uservals [i][j]

Answer 1

The correct expressions to find the minimum value in a two-dimensional array are 'userVals[i][j]' for XXX and 'minVal = userVals[i][j]' for YYY, using a nested for loop to iterate over the elements.

Step-by-step explanation:

The question is asking for the correct expressions to find the minimum value of all the elements in a two-dimensional array in C/C++ programming. To find the minimum value in the array, you need to compare each element with the current minimum value and update the minimum value if a smaller element is found. The correct expressions to use are userVals[i][j] for XXX and minVal = userVals[i][j] for YYY. Here is the completed loop:

int minVal = userVals[0][0];
for (int i = 0; i < NUM_ROWS; ++i) {
for (int j = 0; j < NUM_COLS; ++j) {
if (userVals[i][j] < minVal) {
minVal = userVals[i][j];
}
}
}

This nested for loop iterates through all elements in the array and updates minVal whenever it finds an element smaller than the current minimum.