asked 71.6k views
3 votes
Suppose you have an ANOVA with 5 treatments and 6 observations per treatment. Given the following partial ANOVA table, what would the sum of squares treatment be?

Source Sum of Squares Degrees of freedom Mean Square E
Treatment 6.250
Error 12.000
Total

a. 300
b. 25
c. 4
d. 75
e. There is not enough information to make such calculation

asked
User PeteH
by
7.6k points

1 Answer

7 votes

The sum of squares for treatment is calculated as the mean square for treatment multiplied by the degrees of freedom for treatment, resulting in 25. Therefore, the answer is b. 2.

The sum of squares for treatment (SSTr) is calculated by multiplying the mean square for treatment by the degrees of freedom for treatment. The degrees of freedom for treatment (DFTr) is equal to the number of treatments minus 1, which is 5 - 1 = 4.

The formula is
\(SSTr = MSr * DFTr\), where MSr is the mean square for treatment.

In the provided partial ANOVA table, the mean square for treatment (MSr) is given as 6.25.


\[SSTr = 6.25 * 4 = 25\]

Therefore, the sum of squares for treatment is 25. The correct answer is b.25 .

answered
User Sfinkens
by
8.0k points
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