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Defining the error function erf x by erf x= 2/√π∫ˣ₀ e⁻ᵗ²

Obtain an aspmptotic expansion as x≥0 and one as x→[infinity].

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User Lynxi
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1 Answer

4 votes

Final answer:

The error function, erf(x), can be defined as an integral. To obtain an asymptotic expansion for erf(x) as x ≥ 0, we can use the power series expansion of the exponential function. As x approaches infinity, we can use Laplace's method to find the asymptotic expansion.

Step-by-step explanation:

The error function, erf(x), can be defined as an integral:

erf(x) = (2/√π) ÞE;x0 e-t2 dt

To obtain an asymptotic expansion for erf(x) as x ≥ 0, we can use the power series expansion of the exponential function:

ex = 1 + x + (x2/2!) + (x3/3!) + ...

By substituting this series into the integral for erf(x) and simplifying, we can obtain the asymptotic expansion.

As x approaches infinity, we can use a different expansion technique called Laplace's method. This involves finding the maximum of the exponent in the integrand and then using a Taylor series expansion around that maximum.

By applying these methods, we can obtain the asymptotic expansions for erf(x) as x ≥ 0 and as x approaches infinity.

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User Bane
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