Question

-3(y-2)<=18, or ,15+y<19 eps, solve the overall inequality problem and express you

Answer 1

The compounded inequality -3(y-2)≤18 or 15+y<18 is solved by treating each part separately. The solution to the inequalities is that y can be any number between -4 and 3, including -4 but not including 3.

Step-by-step explanation:

The question asks to solve the compounded inequality -3(y-2)≤18, or, 15+y<18. We'll start by solving each inequality separately and then combine the results.

For the first inequality -3(y-2)≤18:

1. Distribute -3 inside the parentheses: -3*y + 6 ≤ 18.
2. Subtract 6 from both sides: -3*y ≤ 12.
3. Divide both sides by -3, remembering to reverse the inequality sign: y ≥ -4.

For the second inequality 15+y<18:

1. Subtract 15 from both sides: y < 3.

Combining the results from both inequalities:

• y ≥ -4
• y < 3

The overall solution to the compounded inequality is all values of y that satisfy y ≥ -4 and y < 3. So y can be any number between -4 and 3, including -4 but not including 3.