Question

How many moles are in 3.30 x 1024 molecules of N2I6

Answer 1

Divide the number of molecules N by avogadro's constant.

Let n be the number of moles then,

`n=(N)/(N_A)=(3.3\cdot10^(24))/(6.022\cdot10^(23))=5.48\mathrm{mol}`

Hope this helps.