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Factor the trinomial of the form x² + bx + c. (If the polynomial is prime, enter PRIME.)

n² + 21n + 54

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User Korunos
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1 Answer

6 votes

Final answer:

To factor the trinomial n² + 21n + 54, we find the factor pair of the constant term (+54) that adds up to the coefficient of the middle term (+21), which are 6 and 9, resulting in (n + 6)(n + 9). For quadratic equations that cannot be factored, the quadratic formula is used to determine the roots.

Step-by-step explanation:

To factor the trinomial n² + 21n + 54, we need to find two numbers that multiply to give +54 (the constant term) and add up to +21 (the coefficient of the middle term). By looking for factor pairs of 54, we find that 6 and 9 fulfill these conditions because 6 × 9 = 54 and 6 + 9 = 15. Therefore, the trinomial can be factored as (n + 6)(n + 9).

If we have a quadratic equation ax² + bx + c = 0, and factoring is not possible or straightforward, the quadratic formula can be used to find the roots of the equation. The quadratic formula is given by x = (-b ± √(b² - 4ac)) / (2a). This formula is essential for solving any quadratic equation when factoring is not an option.

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User Shutupchigo
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