Question

Determine who had the correct answer in Misha's group for the given expression: 7y^2z + 3yz^2 - 3.

Answer 1

To determine who had the correct answer in Misha's group, evaluate the expression for each option using the given values and simplify.

Step-by-step explanation:

To determine who had the correct answer in Misha's group for the expression 7y^2z + 3yz^2 - 3, we need to evaluate the given expression for each member in the group. Let's substitute the values from each option and simplify:

1. Option (a): x = 2, y = 2, z = 2. Substitute these values into the expression: 7(2)^2(2) + 3(2)(2)^2 - 3 = 7(4)(2) + 3(2)(4) - 3 = 56 + 24 - 3 = 77.
2. Option (b): x = 1, y = 3, z = 0. Substitute these values into the expression: 7(3)^2(0) + 3(3)(0)^2 - 3 = 7(9)(0) + 3(3)(0) - 3 = 0 + 0 - 3 = -3.
3. Option (c): x = 400, y = 2101, z = 320. Substitute these values into the expression: 7(2101)^2(320) + 3(2101)(320)^2 - 3 = 7(8828403200) + 3(2101)(102400) - 3 = 61798822400 + 6429849600 - 3 = 68228672097.

Based on our calculations, option (c) had the correct answer of 68228672097.