Question

Calculate the change in temperature resulting from adding 31.3 kJ of heat to a 450 g block of aluminum. The specific heat of aluminum is 0.90 J/gºC.

Answer 1

To determine the change in temperature of an aluminum block, the formula Q = mc∆T is used. With an added heat of 31.3 kJ, a mass of 450 g, and a specific heat capacity of 0.90 J/g°C, the temperature change is calculated to be approximately 77.28°C.

Step-by-step explanation:

To calculate the change in temperature when heat is added to a block of aluminum, we use the formula Q = mc∆T, where Q is the heat added, m is the mass of the aluminum, c is the specific heat capacity of aluminum, and ∆T is the change in temperature. We are given:

• Q = 31.3 kJ (which is 31,300 J because there are 1,000 Joules in one kJ)
• m = 450 g
• c = 0.90 J/g°C

Rewriting the equation to solve for ∆T, we get:

∆T = Q / (mc)

Substituting in the given values:

∆T = 31,300 J / (450 g × 0.90 J/g°C)

After performing the division, we find the change in temperature:

∆T = 31,300 J / (405 J/°C)

∆T = 77.28°C

The change in temperature of the aluminum block is therefore approximately 77.28°C.