Final answer:
To find the total resistance in a parallel DC circuit with three branches, use the formulas for equivalent resistance and add the results together. In this case, the total resistance is 327 Ω.
Step-by-step explanation:
To find the total resistance in a parallel DC circuit with three branches, we need to calculate the equivalent resistance. In this case, R₂ and R₃ are in parallel, so we can find Rp using the formula:
Rp = (R₂ * R₃) / (R₂ + R₃)
Once we have Rp, we can find the total resistance (Rtot) by adding R₁ and Rp:
Rtot = R₁ + Rp
In this specific scenario, the values of R₁, R₂, and R₃ are given as 16 S², 242, and 32 92, respectively. By performing the calculations, we find that the total resistance is equivalent to 327 Ω.
The total resistance in a parallel circuit with resistors of 16 Ω, 24 Ω, and 32 Ω is found using the formula for equivalent resistance in parallel, resulting in approximately 7.38 Ω.
To find the total resistance in a parallel circuit, you would use the formula for the equivalent resistance of parallel resistors, which is 1/Req = 1/R1 + 1/R2 + 1/R3. Given the resistances 16 Ω, 24 Ω, and 32 Ω, you can calculate the equivalent resistance as follows:
1/Req = 1/16 + 1/24 + 1/32
1/Req = (3/48) + (2/48) + (1.5/48)
1/Req = 6.5/48
Req = 48 / 6.5
Req = 7.38 Ω (rounded to two decimal places)
Therefore, the total resistance of the parallel circuit is approximately 7.38 Ω.