Final answer:
To determine the time it will take for the concentration of A to drop from 0.75 M to 0.25 M in a reaction with rate constant 6.00*10^-3 L mol^-1 min^-1, you can use the first-order rate equation
Step-by-step explanation:
To determine the time it will take for the concentration of A to drop from 0.75 M to 0.25 M, you can use the first-order rate equation:
ln([A]t/[A]0) = -kt
Where [A]t is the final concentration of A, [A]0 is the initial concentration of A, k is the rate constant, and t is the time.
Plugging in the values: [A]t = 0.25 M, [A]0 = 0.75 M, k = 6.00*10^-3 L mol^-1 min^-1
ln(0.25/0.75) = -(6.00*10^-3)(t)
Solving for t: t = ln(0.25/0.75) / -(6.00*10^-3)
Using a calculator: t ≈ 76.07 minutes