Question

Q3: Given the below signals:

m(t)=5cos(12×10
6
πt+80
∘
)
c(t)=3cos(16×10
6
πt+60
∘
)
​
If the energy spectrum of the signal S
E
​
(f) equals 8.445×10
−8
, find f

Answer 1

The amplitude of the wave is 30, the frequency is 4.0x10^6 Hz, and the period is 1/(4.0x10^6) seconds. The graph of the electric field would show a sine wave with an amplitude of 30.

Step-by-step explanation:

The amplitude of a wave is the maximum displacement of the wave from its equilibrium position. In this case, the amplitude of the wave is 30.

The frequency of a wave is the number of complete cycles or oscillations it makes per second. In this case, the frequency of the wave is 4.0x10^6 Hz.

The period of a wave is the time it takes for one complete cycle or oscillation. The period can be calculated as the reciprocal of the frequency. In this case, the period of the wave is 1/(4.0x10^6) seconds.

A graph for this electric field would have time on the x-axis and the electric field strength on the y-axis. The graph would show a sine wave with an amplitude of 30.