Question

A baseball is projected upward from the top of a 448-ft-tall building with an initial velocity of 48 feet per second. The height, ℎ, of the baseball above the ground at any time, , in seconds, is given by the equation ℎ() = −16^2 + 48 + 448.

Find the height after 2 seconds

Answer 1

To find the height of the baseball after 2 seconds, you substitute t = 2 into the equation h(t) = -16t^2 + 48t + 448, resulting in a height of 480 feet above the ground.

Step-by-step explanation:

The height of the baseball after 2 seconds can be found by substituting t = 2 into the given equation, h(t) = -16t2 + 48t + 448. Plugging 2 seconds into the equation results in:

h(2) = -16(2)2 + 48(2) + 448,

h(2) = -16(4) + 96 + 448,

h(2) = -64 + 96 + 448,

h(2) = 480 feet.

Therefore, the height of the baseball above the ground after 2 seconds is 480 feet.