Final answer:
Perform a hypothesis test to determine if the mean number of concurrent users has increased. The null hypothesis is that the mean has not increased (μ = 8000), and the alternative hypothesis is that it has increased (μ > 8000). Compare the z-value test statistic to the critical value at a 10% significance level to conclude.
Step-by-step explanation:
To assess whether the mean number of concurrent users for an internet service provider has significantly increased after an equipment upgrade, we need to perform a hypothesis test. The null hypothesis (H0) is that the mean number of users has not increased, implying μ = 8000. The alternative hypothesis (Ha) is that the mean number has increased, so μ > 8000.
To calculate the test statistic, we use the formula: z = (x - μ) / (σ / √n), where x is the sample mean (8100), μ is the population mean (8000), σ is the standard deviation (900), and n is the sample size (49). Plugging in the values gives us a z-value.
At a 10% level of significance, the z-value should be compared with the critical value from the Z-table that corresponds to a 90% confidence level (z-critical value). If the calculated z-value is greater than the z-critical value, we reject the null hypothesis. Otherwise, we do not reject it.
In conclusion, if our calculated test statistic z is greater than the z-critical value, we have significant evidence at a 10% significance level to suggest that the mean number of users has increased post-upgrade. Otherwise, we do not have sufficient evidence to support the claim that the mean has increased, and therefore would not reject the null hypothesis.