Question

A coyote chased a rabbit 65.0 meters west to a bush and then chased it another 23.2 meters west before catching it. If the entire chase lasted 97 seconds, what was the average velocity of the chase?

A. 90.93 m/s
B. 91.93 m/s
C. 89.93 m/s
D. 181.86 m/s

Answer 1

The coyote's average velocity is determined by dividing the total westward displacement of 88.2 meters by the total time of the chase, 97 seconds, resulting in approximately 0.91 m/s to two decimal places.

Step-by-step explanation:

The average velocity of a coyote during its chase can be calculated by dividing the total displacement by the total time of the chase. The coyote chases the rabbit 65.0 meters west, and then an additional 23.2 meters west, resulting in a total displacement of 65.0 + 23.2 = 88.2 meters west. Given that the entire chase lasted 97 seconds, the average velocity v is v = displacement / time = 88.2 m / 97 s = 0.9087 m/s. Since the chase is towards the west, the average velocity is in the westward direction. Therefore, the absolute value gives us the magnitude of the average velocity, which is approximately 0.91 m/s to two decimal places.