Question

For a data set of the pulse rates for a sample of adult females, the lowest pulse rate is 35 beats per minute, the mean of the listed pulse rates is x = 72.0 beats per minute, and their standard deviation is s = 24.6 beats per minute.

a. What is the difference between the pulse rate of 35 beats per minute and the mean pulse rate of the females?
b. How many standard deviations is that the difference found in part (a)?
c. Convert the pulse rate of 35 beats per minutes to a z score
d. If we consider pulse rates that convert to z scores between -2 and 2 to be neither significantly low nor significantly high, is the pulse rate of 35 beats per minute significant?
a. The difference is beats per minute.
(Type an integer or a decimal. Do not round.)
b. The difference is standard deviations
(Round to two decimal places as needed.)
c. The z score is 2-0
(Round to two decimal places as needed.)
d. The lowest pulse rate is significantly high significantly low. not significant.

Answer 1

The difference between the pulse rate of 35 beats per minute and the mean pulse rate of the females is 37 beats per minute. This difference is equivalent to 1.50 standard deviations. The pulse rate of 35 beats per minute is not significant according to the given criteria.

Step-by-step explanation:

a. The difference between the pulse rate of 35 beats per minute and the mean pulse rate of the females is 72.0 - 35 = 37 beats per minute.

b. To find the difference in standard deviations, we divide the difference between the two values by the standard deviation: 37 / 24.6 = 1.50 standard deviations.

c. To convert the pulse rate of 35 beats per minute to a z-score, we subtract the mean from the pulse rate and divide by the standard deviation: (35 - 72) / 24.6 = -1.50.

d. Since the z-score of -1.50 falls within the range of -2 to 2 (considered neither significantly low nor significantly high), the pulse rate of 35 beats per minute is not significant.