Question

on angela's calendar, one year is composed of 15 months, and each month always consists of 30 days. on that calendar, there are 5 days in a week, which are monday, tuesday, wednesday, thursday and friday. if today is monday, then tomorrow will be tuesday, the day after tomorrow will be wednesday. after 5 days it will be monday. today is the d1-th day in the m1-th month of year y1. given the day of today on angela's calendar, what day will it be (or was it) on the d2-th day in the m2-th month of year y2 on angela's calendar?

Answer 1

In Angela's calendar, each month has 30 days and there are 5 days in a week. To find the day on a specific date, you need to calculate the difference in days and divide it by 5 to determine the day.

Step-by-step explanation:

In Angela's calendar, one year is composed of 15 months, and each month always consists of 30 days. There are 5 days in a week, which are Monday, Tuesday, Wednesday, Thursday, and Friday.

If today is Monday, then tomorrow will be Tuesday, the day after tomorrow will be Wednesday. After 5 days it will be Monday again.

To find out the day on the d2-th day in the m2-th month of year y2 on Angela's calendar, we need to find the difference in days between the two given dates. Then, we can divide this difference by 5, because the days repeat every 5 days. Finally, we can calculate the remainder to determine the day.