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One evening, 750 tickets were sold for a local Community College spring musical. Tickets cost $3 for students and $5 for non-students. Total receipts were $3066. Find the number of student tickets and non-student tickets."

A) Students: 450, Non-students: 300
B) Students: 300, Non-students: 450
C) Students: 500, Non-students: 250
D) Students: 250, Non-students: 500

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User Soimort
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1 Answer

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Final answer:

Upon solving the system of equations, it was found that 342 student tickets and 408 non-student tickets were sold. This answer is not listed among the provided options, indicating a possible error in the question or answer choices.Students: 250, Non-students: 500

Step-by-step explanation:

The question asks us to determine the number of student tickets and non-student tickets sold for a community college spring musical, given that student tickets cost $3 each, non-student tickets cost $5 each, a total of 750 tickets were sold, and the total receipts were $3066.Let's denote the number of student tickets as s and the number of non-student tickets as n. We have two equations from the information given:To solve this problem, we can set up a system of equations. Let x be the number of student tickets sold and y be the number of non-student tickets sold. We are given two pieces of information:The total number of tickets sold is 750: x + y = 750The total receipts were $3066: 3x + 5y = 3066We can solve this system of equations using substitution or elimination. Here, we will use substitution.From the first equation, we can solve for x in terms of y: x = 750 - y.Substituting this into the second equation:3(750 - y) + 5y = 30662250 - 3y + 5y = 30662y = 816y = 408Now, we can substitute this value of y back into the first equation to find x:x + 408 = 750x = 342Therefore, the number of student tickets sold is 342 and the number of non-student tickets sold is 408.s + n = 750 (total tickets3s + 5n = 3066 (total receipts)To solve this system of equations, we can use the substitution or elimination method.

For simplicity, let's use the elimination method:Multiply the first equation by 3 to get: 3s + 3n = 2250Now subtract this new equation from the second equation provided by the problem: (3s + 5n = 3066) - (3s + 3n = 2250), which simplifies to 2n = 816.Dividing both sides of the equation by 2, we find n = 408 non-student tickets.To find s, plug the value of n back into the first equation: s + 408 = 750, which simplifies to s = 342 student ticketsTo solve this problem, we can set up a system of equations. Let x be the number of student tickets sold and y be the number of non-student tickets sold. We are given two pieces of information:The total number of tickets sold is 750: x + y = 750The total receipts were $3066: 3x + 5y = 3066We can solve this system of equations using substitution or elimination. Here, we will use substitution.From the first equation, we can solve for x in terms of y: x = 750 - y.Substituting this into the second equation:3(750 - y) + 5y = 3066- 3y + 5y = 30662y = 816y = 408Now, we can substitute this value of y back into the first equation to find x:x + 408 = 750x = 342Therefore, the number of student tickets sold is 342 and the number of non-student tickets sold is 40Therefore, the correct answer is not explicitly listed in the options, which means there might be an error in the question or the provided choices.

answered
User Pyko
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