Question

A 1-gram sample of K2CO3 is dissolved in enough water to make 250 ml of solution. A 25 ml aliquot is taken and titrated with 0.1 M HCl.

What is the molarity of K2CO3 in the original solution?
A) 0.1 M
B) 0.25 M
C) 0.5 M
D) 1.0 M

Answer 1

To find the molarity of K2CO3 in the original solution, we need to use the concept of stoichiometry. In this case, the molarity of K2CO3 in the original solution is 0.1 M. Option D is correct.

Step-by-step explanation:

To find the molarity of K2CO3 in the original solution, we need to use the concept of stoichiometry.

First, we need to find the moles of K2CO3 in the 25 ml aliquot.

The volume of the original solution is 250 ml, so we can calculate the moles of K2CO3 in the entire solution.

Finally, we divide the moles of K2CO3 by the volume (in liters) of the entire solution to obtain the molarity.

In this case, the molarity of K2CO3 in the original solution is 0.1 M.