Question

the laser line for raman spectroscopy measurements of 14n2 molecules is set to 20,487 cm-1. what is the energy of the first stokes line in cm-1? the rotational constant of 14n2 is 2 cm-1.

Answer 1

The energy of the first Stokes line in Raman spectroscopy can be calculated using the formula E = E_initial - E_final, where E_initial is the energy of the incident laser line and E_final is the energy of the first Stokes line. By substituting the given values and considering the rotational constant, we can find the energy of the first Stokes line in cm-1.

Step-by-step explanation:

To find the energy of the first Stokes line in Raman spectroscopy, we can use the formula:

E = Einitial - Efinal

Where Einitial is the energy of the incident laser line and Efinal is the energy of the first Stokes line. Given that the rotational constant of 14N2 is 2 cm-1, we can calculate the energy of the first Stokes line:

Efinal = Einitial - 2 cm-1

Considering that 1 cm-1 is equal to 11.96 J/mol, we can convert the energy to J/mol if necessary.

Therefore, the energy of the first Stokes line in cm-1 is Efinal = 20,487 cm-1 - 2 cm-1 = 20,485 cm-1.