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What is 1/3n-1/6n+2/3+1/6m

1 Answer

7 votes

The value of
\[ (1)/(3n) - (1)/(6n) + (2)/(3) + (1)/(6m) \] is
\[ (26)/(6n) + (1)/(6m) \].


\[ (1)/(3n) - (1)/(6n) + (2)/(3) + (1)/(6m) \]

We can find a common denominator for the fractions and combine them:


\[ (2)/(6n) - (1)/(6n) + (4)/(6) + (1)/(6m) \]

Now, combine the like terms:


\[ (1)/(6n) + (4)/(6) + (1)/(6m) \]

To make the addition easier, you can express the constants with a common denominator of 6:


\[ (1)/(6n) + (24)/(6) + (1)/(6m) \]

Now, combine the terms:


\[ (1 + 24 + 1)/(6n) + (1)/(6m) \]


\[ (26)/(6n) + (1)/(6m) \]

answered
User Noamyg
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