Question

assuming independent assortment for all gene pairs, what is the probability that a parent with the genotype aabbcc, will produce a gamete with the allele combination abc? question 5answer a. 1/8 b. 1/2 c. 9/16 d. 1/16 e. 1/4

Answer 1

The probability that a parent with the genotype aabbcc will produce a gamete with the allele combination abc is 1/8, considering independent assortment of each gene pair.

Step-by-step explanation:

The probability that a parent with the genotype aabbcc will produce a gamete with the allele combination abc can be calculated assuming independent assortment for all gene pairs.

Each gene pair sorts independently, meaning the allele for one gene does not influence the allele for another gene. The individual in question can produce gametes with different combinations of the three gene pairs involved. For a single gene, the probability that one allele is included in a gamete is 1/2 (just as a tossed coin has a 50% chance of landing on heads).

For aabbcc, the probability for each allele being represented in the gamete (A or a, B or b, C or c) is 1/2. So, to calculate the probability of producing a gamete with abc, we multiply the probabilities of each independent assortment: 1/2 (for a) x 1/2 (for b) x 1/2 (for c), which equals 1/8.

Thus, the correct answer to the question of what is the probability that a parent with the genotype aabbcc will produce a gamete with the allele combination abc is A. 1/8.