Question

a squirrel drops an acorn into the head of an unsuspecting dog. The acorn falls 4.0 m4.0m4, point, 0, start text, m, end text before it lands on the dog. We can ignore air resistance.

Answer 1

The squirrel's velocity just before hitting the ground, assuming it fell from a height of 3.0 m, can be calculated using the equation vf = sqrt(2 * g * h). Plugging in the values, we find that the squirrel's velocity is 7.7 m/s.

Step-by-step explanation:

In this scenario, we can use the laws of physics to calculate the squirrel's velocity just before it hits the ground. We can ignore air resistance, which means we only need to consider the effect of gravity. The equation we can use is:

vf = sqrt(2 * g * h)

Where vf is the final velocity, g is the acceleration due to gravity (9.8 m/s^2), and h is the height from which the squirrel falls (3.0 m). Plugging in these values, we get:

vf = sqrt(2 * 9.8 * 3.0) = 7.7 m/s

Therefore, the squirrel's velocity just before hitting the ground is 7.7 m/s.