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3 votes
What is the value of lim(h→0) (16h)^14 - 2h?
a) 0
b) 1
c) 16
d) 14

asked
User Lukehawk
by
8.1k points

1 Answer

0 votes

Final Answer:

The value of lim
(h→0) (16h)14 - 2h a) 0.

Step-by-step explanation:

In the given expression, as h approaches 0, the term
(16h)14 dominates the expression since any non-zero value raised to the power of 14 will be significantly greater than 2h as h approaches 0.

Therefore, the entire expression tends towards 0 as h approaches 0. This is because the second term, 2h, becomes negligible compared to the first term, and the result approaches zero.

In calculus, this type of limit calculation involves recognizing the dominant term and ignoring the less influential terms as they become insignificant when h approaches 0.

In summary, the limit of the given expression as h approaches 0 is 0, making option (a) the correct answer.

answered
User Ljedrz
by
7.6k points
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