Question

The empirical formula is C6H6O.vapour density is 47.find the molecular formula​

Answer 1

Answer: The molecular formula will be
`C_6H_6O`

Step-by-step explanation:

Molecular formula is the chemical formula which depicts the actual number of atoms of each element present in the compound.

Empirical formula is the simplest chemical formula which depicts the whole number of atoms of each element present in the compound.

The empirical formula is
`C_6H_6O`

The empirical weight of
`C_6H_6O` = 6(12)+6(1)+1(16) = 94 g.

The molecular weight =
`2* \text{vapour density}=2* 47=94`

Now we have to calculate the molecular formula.

`n=\frac{\text{Molecular weight}}{\text{Equivalent weight}}=(94)/(94)=1`

The molecular formula will be=
`1* C_6H_6O=C_6H_6O`