Question

I had to hire a plumber to come fix a leaky pipe. The first day he worked 3 hours and charged me $450. The next day he came back and finished the job working another 5 hours charging me $700. Find the equation that represents the cost, y, after x hours of working.​

Answer 1

143.75X = Y

Step-by-step explanation:

Since I had to hire a plumber to come fix a leaky pipe, and the first day he worked 3 hours and charged me $ 450, while the next day he came back and finished the job working another 5 hours charging me $ 700, to find the equation that represents the cost, and, after x hours of working, the following calculation must be performed:

(450 + 700) / (3 + 5) = Y

1150/8 = Y

143.75 = Y

Thus, the hourly cost of the plumber's work was $ 143.75.