Final answer:
The question asks for the limit of (3x^3-2x)/(x^2.2x.8) as x approaches negative infinity, which simplifies to the limit of 3/16 when considering the leading terms in both the numerator and denominator.
Step-by-step explanation:
The subject of this question is Mathematics, and it falls under the domain of calculus, specifically the topic of limits as x approaches negative infinity. The question appears to be at a High School level.
To find the limit as x approaches infinity, we typically look at the leading terms in the numerator and denominator. If you mean to evaluate the function (3x3-2x)/(x2·2x·8), then as x approaches negative infinity, the highest power of x in the numerator and denominator dominates the behavior of the function. The limit is thus found by dividing the leading coefficients: lim x→-∞ (3x3-2x)/(x2·2x·8) = lim x→-∞ (3x3)/(16x3) = 3/16.
The rest of the provided information seems unrelated to evaluating this calculus limit and may not be relevant to this particular problem.