asked 152k views
2 votes
How many numbers not exceeding 10000 can be made using the digits 2,4,5,6,8 if repetition of digits is allowed?

a. 740
b. 9999
c. 780
d. 820

1 Answer

3 votes

Final answer:

There are 780 different numbers not exceeding 10000 that can be made using the digits 2,4,5,6,8 if repetition of digits is allowed. Calculations are based on combinations for 1 to 4-digit long numbers.

Step-by-step explanation:

To find how many numbers not exceeding 10000 can be made using the digits 2,4,5,6,8 with repetition allowed, we have to consider numbers of different lengths (1 to 4 digits) separately.

For a 1-digit number, there are 5 choices (2, 4, 5, 6, or 8).

For a 2-digit number, there are 5 choices for the first digit and 5 choices for the second digit, making a total of 5 x 5 = 25 combinations.

For a 3-digit number, there are 5 choices for the first digit, 5 choices for the second digit, and 5 choices for the third digit resulting in 5 x 5 x 5 = 125 combinations.

For a 4-digit number, there are 5 choices for each of the four digits so, 5 x 5 x 5 x 5 = 625 combinations.

Add up all the possibilities for 1-digit, 2-digit, 3-digit, and 4-digit numbers: 5 + 25 + 125 + 625 = 780.

Therefore, there are 780 different numbers that can be created using the digits 2,4,5,6,8 without exceeding 10000.

Therefore answer is c. 780.

answered
User Rogier Spieker
by
7.4k points
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