Question

whatever the source of water. similarly, carbon dioxide contains carbon to oxygen in a 3:8(12:32) ratio. in ammonia, nitrogen and hydrogen are present in the ratio of 14:3 by mass.a sample of calcium carbonate contains 25% of calcium, 11% of carbon, and 43% of oxygen. applying the law of constant proportion, find the mass of calcium, carbon, and oxygen in 20.0 g of calcium carbonate prepared by another method

Answer 1

The masses of calcium, carbon, and oxygen in 20.0 g of calcium carbonate, according to the Law of Constant Proportion, are 5.0 g, 2.2 g, and 12.8 g respectively.

Step-by-step explanation:

By applying the Law of Constant Proportion we can find the mass of calcium, carbon, and oxygen in 20.0 g of calcium carbonate prepared by another method. According to the given percentages:

• Mass of calcium = 25% of 20.0 g = 0.25 × 20.0 g = 5.0 g
• Mass of carbon = 11% of 20.0 g = 0.11 × 20.0 g = 2.2 g
• Mass of oxygen = Remaining percentage of the compound = 100% - (25% + 11%)

= 64% of 20.0 g

= 0.64 × 20.0 g

= 12.8 g

These calculations are based on the fact that in calcium carbonate (CaCO₃), the elements calcium, carbon, and oxygen are always present in a consistent fixed ratio by mass, which is due to the Law of Definite Proportions.