Question

A 12,000 Ω resistor is rated at 2.5 watts. What is the maximum voltage of electricity that should be connected across it? Round your answer to two decimal places, if necessary.

Answer 1

The maximum voltage that can be connected across a 12,000 Ω resistor rated at 2.5 watts is approximately 173.21 volts, calculated using the formula V = √(P × R).

Step-by-step explanation:

The question involves calculating the maximum voltage that can be applied to a 12,000 Ω resistor rated at 2.5 watts. To find this voltage, we can use the power formula related to resistance and voltage, which is:

P = V^2 / R

Where P represents power in watts, V represents voltage in volts, and R represents resistance in ohms. By rearranging this formula to solve for V, we obtain:

V = √(P × R)

Substituting the given values for power (P = 2.5 W) and resistance (R = 12,000 Ω) into this formula, we calculate the maximum voltage as follows:

V = √(2.5 W × 12,000 Ω)

V = √(30,000 WΩ)

V = 173.21 volts

Therefore, the maximum voltage that should be connected across a 12,000 Ω resistor rated at 2.5 watts is approximately 173.21 volts.