Question

A 1.13 kg ball is swung vertically from a 0.50 m cord in uniform circular motion at a speed of 2.4 m/s.

A) what is the tension in the cord at the bottom of the balls motion?

B) what is the tension in the cord at the top of the ball's motion?

C) what is the tension on the cord when the ball is horizontal on the right side?

Answer 1

The tension in the cord is 24.1 Newton

Step-by-step explanation:

Step 1: Data given

mass of the ball = 1.13 kg

Cord = 0.50m

velocity = 2.4 m/s

Step 2: Calculate the tension

Fnet = F(c)

T - F(g) = F(c)

⇒ with F(g) = force of gravity = m*g

⇒ with F(C) = centripetal force = (mv²)/r

T = (mv²)/r + mg

⇒ with m = mass = 1.133 kg

⇒ with v = velocity = 2.4 m/s

⇒ with r = radius = 0.50 m

T = (1.13 * 2.4²) / 0.50 + 1.13 * 9.81

T = 24.1 Newton

The tension in the cord is 24.1 Newton.