Question

One mole of an ideal gas initially at a temperature of T₁ = 0.6°C undergoes an expansion at a constant pressure of 1.00

atm to three times its original volume.
(a) Calculate the new temperature Ty of the gas.
K
(b) Calculate the work done on the gas during the expansion.
kJ

Answer 1

The new temperature of the gas (Ty) is 1.8°C. The work done on the gas during the expansion is -2V1 atm.

To calculate the new temperature (Ty) of the gas, we can use the ideal gas law equation:

P₁V₁/T₁ = P₂V₂/Ty

Since the pressure (P) and volume (V) of the gas are constant throughout the process, we can simplify the equation to:

Ty = T₁ * (V₂ / V₁)

Substituting the given values, we get:

Ty = 0.6°C * (3/1) = 1.8°C

To calculate the work done on the gas during the expansion, we can use the equation:

Work = -PΔV

Where ΔV is the change in volume. In this case, ΔV = V₂ - V₁ = 3V₁ - V₁ = 2V₁.

Substituting the given values, we get:

Work = -1.00atm * 2V₁ = -2V₁atm