Question

A population of sheep is in Hardy-Weinberg equilibrium. The allele for white wool (W) has an allele frequency of 0.19, and the allele for black wool (w) has an allele frequency of 0.81.

a. 31%
b. 4%
c. 66%
d. 15%

Answer 1

The Hardy-Weinberg model describes genetic equilibrium and uses an equation to calculate genotype frequencies. In this case, the frequency of the AA genotype can be determined using the frequency of the dominant allele.

Step-by-step explanation:

The Hardy-Weinberg model of population genetics describes how a population can remain in genetic equilibrium. In this equilibrium, the frequency of alleles remains stable from generation to generation. The Hardy-Weinberg equation is represented by p² + 2pq+q² = 1, where p represents the frequency of the dominant allele (W) and q represents the frequency of the recessive allele (w).

To find the frequency of the AA genotype (p²), you need to square the frequency of the dominant allele (p). Since the frequency of the dominant allele is 0.19, you would calculate 0.19² = 0.0361. Therefore, the frequency of the AA genotype is 0.0361 or 3.61%.