Question

Part three to my other questions, thank you to anyone that helps!!

Answer 1

The quadratic equations are solved using the quadratic formula, providing multiple solutions for each equation.

The provided equations are quadratic expressions, and to solve them, we can use the quadratic formula
`\(x = (-b \pm √(b^2 - 4ac))/(2a)\)`, where (a), (b), and (c) are coefficients of the quadratic equation in the form
`\(ax^2 + bx + c = 0\)`.

1.
`\(2x^2 - 11 - 9x = 0\)`: Applying the quadratic formula yields two solutions.

2.
`\(x^2 = -7x - 10\)`: Rearranging and applying the quadratic formula provides the solutions.

3.
`\(x^2 - 12x = -32\)`: By bringing all terms to one side, we get a quadratic equation, and the quadratic formula helps find the solutions.

4.
`\(x^2 = -x + 12\)`: Similar to the previous equations, the quadratic formula is applied to find the solutions.

5.
`\(42 = x^2 + x\)`: Rearranging and using the quadratic formula yields the solutions.

6.
`\(10x^2 - 48 = -74x\)`: Converting to standard form and applying the quadratic formula gives the solutions.

7.
`\(x^2 + x = 2\)`: Rearranging and using the quadratic formula helps find the solutions.

8.
`\(76 = x^2 + 2x\)`: Rearranging and applying the quadratic formula provides the solutions.

In summary, the quadratic equations are solved using the quadratic formula, yielding multiple solutions for each equation.