How many grams of aluminum are required to produce 3. 5 moles al2o3.

Question

asked May 20, 2023 34.0k views

1 Answer

Bobrobbob · Answer 1 · 2023-05-25T03:08:56+0000

Answer:

189 g of Aluminum

Step-by-step explanation:

3.5 moles of Al2O3 has a total mass of 357 g roughly. There is 189 g of Aluminum, and 168 g of Oxygen which adds up to 357 g of Al2O3.